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X^2+12X=23
We move all terms to the left:
X^2+12X-(23)=0
a = 1; b = 12; c = -23;
Δ = b2-4ac
Δ = 122-4·1·(-23)
Δ = 236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{236}=\sqrt{4*59}=\sqrt{4}*\sqrt{59}=2\sqrt{59}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{59}}{2*1}=\frac{-12-2\sqrt{59}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{59}}{2*1}=\frac{-12+2\sqrt{59}}{2} $
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